and yes its quite simple , yet they continue to throw red herrings which are disregarded ..

and so many blessings

we are on proof 2 ,and we shall not waiver or get distracted from " pilot principles "  @ 4:50 - 6:25



so as not to derail this thread .



this current line of analysis will, I do believe , bring clarity to this thread

and answer many questions for those that are curious  .

and so if you are interested , and when you are ready ..

until that is answered , I shall be bringing forth more evidence and again ,

this thread is an amalgamation of pertinent material and needs not antagonists and or abuse as we continue

╰დ╮ॐ╭დ╯

not sure why you are still posting if you are not going to answer the topic at hand ..

you keep running , and then saying " oh people think this of you "

clearly I could care less ..lol ! what people think of me sad one ..

the fact is that you are afraid and have seen proof 2 and you cannot answer it .

and here it is again

and so many blessings

we are on proof 2 ,and we shall not waiver or get distracted from " pilot principles "  @ 4:50 - 6:25



so as not to derail this thread .



this current line of analysis will, I do believe , bring clarity to this thread

and answer many questions for those that are curious  .

and so if you are interested , and when you are ready ..

until that is answered , I shall be bringing forth more evidence and again ,

this thread is an amalgamation of pertinent material and needs not antagonists and or abuse as we continue

╰დ╮ॐ╭დ╯

it_is_the_light wrote on Mar 21^st, 2018 at 8:54pm:


Not in the way you think.

Quote:


Again, you've not been providing evidence, only hypothesis born out of ignorance.

Take the second point, the claim which you've tried to support with your SR-71 info states that if a Plane flies level it would gain altitude.

You again have a lack of understanding, this time of basic aviation.  There is flying straight, and flying level, the difference is here:



Now I could leave it at that, but this isn't a meme war, so here are some cold hard facts.

There is some truth to what he says, planes do in fact fly pitched down in order to maintain level flight, it's just your/his math is totally wrong. 

In an airplane, Elevator Trim simply controls the RATE of pitch of an aircraft - not the actual pitch of the plane.

A 747 flying at 35,000' would have a flight circumference of  about 2π*(3959+(35000/5280)) ≈ 24916 miles
Flying at 570 miles per hour, this plane would fly a fraction of the 360° around given by 360*570/24916
Since that's 1 hour we can divide by 60 to get the degrees per hour: 360*570/24916/60 ≈ 0.137°/minute

That is down in the noise since pitch rate is affected by temperature, density, power, and control settings on the plane you simply trim the plane for as close to ZERO vertical speed as you can and you've automatically compensated for all of them at once.  Of course, on a 747 computers do that.  In a small plane the pitch rate is microscopic.

Pitch Rate/minute = 360*groundspeedMPH/[2π*(3959+(altitudeFEET/5280))]/60

So yes, airplanes DO pitch down constantly at an EXTREMELY slow rate which presents absolutely no issue what-so-ever.  Once again, you've failed to understand a phenomena and proceed to run around making absurd claims about it.

Now to your SR-71 bullshit, there are so many things absolutely wrong in this meme I almost don't know where to start. 

Where did they get 2193.13 MPH from?  I get 668.9 mph for the speed of sound at 85,000' and SR-71 nominally goes Mach 3.2 (it can go slightly faster for short periods), that gives me 668.9*3.2 = ~2140.48 mph at 85,000'.   I guess that is "close enough", so I'll use their 2194 mph for this example.  But we're also at 85,000' so I'll add that into our radius of curvature (makes very little difference).

And where did they get '1/4 MILE OF CURVATURE EVERY HOUR' from?  Wow, that is just stupidly wrong.  At 2194 mph, you go 2194 miles in 1 hour and that gives 696.83 Miles OF CURVATURE DROP not 1/4 mile!  *I've assumed no wind so 2194 mph ~ ground distance and I've used CURVED GROUND DISTANCE for the curvature calculation: r/cos(d/r)-r

And even if it was a 1/4 mile 5280/4/60 = 22 FEET, not 23.  Maybe they rounded the .0?  They clearly cannot manage division.

But their worst error is assuming that 1/4 mile of curvature MEANS 22 feet per minute of vertical speed in the first place.  As I've already shown VERTICAL SPEED WOULD BE ZERO AT EVERY POINT.

The curvature 'drop' is BUILT INTO the flight dynamics - the plane isn't flying a linear path and having to drop down, it is flying along the curve -- you have to compute the integral.

The pitch RATE would be:

(360/(2*pi*(3959+(85000/5280))))*(2194)/60 = ~0.527° per minute (~0.00878°/sec)

Still only a very slight rotation that wouldn't be specifically noticeable and would very easily be compensated for in pitch rate - in this case, by the computer that is actually flying the airplane.  But again, the computer doesn't even have to understand the Earth curvature to do this, it just needs to keep VS near zero which is determined by pitch rate and power settings.

YOU DO NOT HAVE TO KEEP ADJUSTING FOR THE CURVATURE - THE RATE OF CURVATURE IS NEAR CONSTANT.

So it isn't the 696.83 miles of curvature drop you need to worry about, let's look at that over 1/1000th of a second:

The plane moves forward ~3.218 feet
The plane pitches forward 0.00000878°
The plane DOES NOT CLIMB 0.00000024669 of a foot (the 'drop' over that distance)

After 1 second the plane HAS NOT CLIMBED 0.24667 feet but it is entirely INACCURATE to say that it has DROPPED 0.24667 feet.   If you take 0.00000024669 * 1000 you'll note that you get 0.00024669  instead of 0.24667 feet -- you are a OFF BY ONE THOUSAND TIMES HERE by assuming this is a linear function.  Every microscopic bit of pitch rotation in between ALREADY ALTERED OUR COURSE.

YOU CANNOT TREAT THESE AS LINEAR AMOUNTS THAT YOU CAN SIMPLY MULTIPLY AND DIVIDE.

It is the sum total of these CONTINUOUS microscopic adjustments that result in the curved flight path.

That is what you don't understand.  With the atrocious math you've cited in this Meme is that any surprise?

Did you even bother to fact check any of this before blindly believing this idiot's video? 

Why do I have to do all your work for you, which you'll ignore anyway?

Flat Earth - Moon Phases and Selenelion Explained

https://aplanetruth.info/2015/03/24/18-is-the-earth-a-sphere-cruisin-at-30000-ft...

#18 Is the Earth a Sphere? Cruisin’ at 30,000 ft.

“….We’ll Be Cruising at 30,000 ft. for the next 4 hours.”

If the Earth were a sphere, airplane pilots would have to constantly correct their altitudes downwards so as to not fly straight off into “outer space!” If the Earth were truly a sphere 25,000 miles circumference curveting 8 inches per mile squared, a pilot wishing to simply maintain their altitude at a typical cruising speed of 500 mph, would have to constantly dip their nose downwards and descend 2,777 feet (over half a mile) every minute! Otherwise, without compensation, in one hour’s time the pilot would find themselves 166,666 feet (31.5 miles) higher than expected!

A plane flying at a typical 35,000 feet wishing to maintain that altitude at the upper-rim of the so-called “Troposphere” in one hour would find themselves over 200,000 feet high into the “Mesosphere” with a steadily raising trajectory the longer they go. I have talked to several pilots, and no such compensation for the Earth’s supposed curvature is ever made. When pilots set an altitude, their artificial horizon gauge remains level and so does their course; nothing like the necessary 2,777 foot per minute declination is ever taken into consideration.

To maintain a 30,000 ft. altitude around a round Earth, the airplane would have to be angled significantly lower than in the rear of the airplane to maintain a 30,000 foot relationship to the Earth’s curvature.

Yet this never, ever happens. When traveling in an airplane it is level form nose to stern.

This means that the Earth is not a globe but is a level piece of land below us while in flight.

If one says that we are in a vacuum and gravity holds us in, then how is plane able to “escape” Earth’s gravity pull upon reaching cruising altitude when NASA tells us that it would require

From the surface of the Earth, escape velocity (ignoring air friction) is about 7 miles per second, or 25,000 miles per hour. Given that initial speed, an object needs no additional force applied to completely escape Earth’s gravity.



Basic Geometry on a Sphere

The Global Earth theorists for 500 years have been telling us the Earth is a sphere. IF the earth is a globe, and is 25,000 English statute miles in circumference, the surface of all standing water must have a certain degree of convexity–every part must be an arc of a circle.

From the summit of any such arc there will exist a curvature or declination of 8 inches in the first statute mile. In the second mile the fall will be 32 inches; in the third mile, 72 inches, or 6 feet, as shown in the diagram above. Spherical trigonometry dictates that a ball-Earth 25,000 miles in circumference would curvate 8 inches per mile varying inversely with the square of the mile, so after six miles there would be an easily detectable and measurable 16 feet, 8 inches of downward curvature.

To determine how much the Earth falls away on the curve you take miles squared X eight inches. This is an inverse relationship so the farther one travels the greater the distance of feet or miles the Earth will fall away.

Let the distance from T to figure 1 represent 1 mile, and the fall from 1 to A, 8 inches; then the fall from 2 to B will be 32 inches, and from 3 to C, 72 inches. In every mile after the first, the curvature downwards from the point T increases as the square of the distance multiplied by 8 inches. The rule, however, requires to be modified after the first thousand miles. 1

Miles squared X 8 inches
one foot = .000189394 miles

Curvature of Earth
1 mile 5.33 ft.  or .12626 mile

10 miles 66.666 ft. or 1.2626 miles

100 miles 6,666.66 ft. or 12.626 miles

So the farther one travels the greater the drop (or rise) in distance.

****

Non NASA camera records continual Flat Earth on plane

Published on Dec 24, 2014
Check out this excellent amateur balloon footage of our flat, motionless Earth! You can clearly see the Sun is NOT 93 million miles away as we’re told. This is evidenced by the hot-spot seen on the clouds directly underneath the Sun as it moves over the Earth. Over 20 miles high and the horizon remains perfectly flat and rises to the eye-level of the observer all the way up. If the Earth were a ball, no matter how big, the horizon could not rise with the observer like this. On a ball-Earth the horizon would stay where it was and you would have to look DOWN to the horizon further and further the higher you rose.

it_is_the_light wrote on Mar 22^nd, 2018 at 2:17pm:


I know you've only copied and pasted that, but do you even understand it?  I could spend the time to show you where you've made simple math errors again, but it's not even your work.

If I was to spend the time to explain where you've gone wrong with the math and the assumptions you've made, would you listen?

Do you even care about understanding this point or are you just trying to win an argument even when you're totally ignorant to it's content?